-2+15x-10x^2=0

Solution for -2+15x-10x^2=0 equation:

-2+15x-10x^2=0

a = -10; b = 15; c = -2;
Δ = b2-4ac
Δ = 152-4·(-10)·(-2)
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{145}}{2*-10}=\frac{-15-\sqrt{145}}{-20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{145}}{2*-10}=\frac{-15+\sqrt{145}}{-20}
$